In a company there are 5 technical employees and 4 non-technical employees. From these employees a committee of four persons is chosen. What is the probability of forming a committee with at least three technical persons?
Total possible committees = C(9,4) = 126
Those possible with 3 technical people = C(5,3)*C(4,1) = 40
Those possible with 4 technical people = C(5,4) = 5
P[ at least three technical persons ] = [ 40 + 5] / 126 =
45 / 126 = 15/42 = 5 / 14 ≈ .357 ≈ 35.7%
+77 
