If there are 7 males and 7 females who all want to be on a committee of 3, what is the probability that exactly two are male?
The total number of possible committies = C(14,3) = 364
And we want to choose any 1 of the 7 females and any 2 of the 7 males....so we have...
C(7,1) * C(7,2) = 147
So...the probability = 147 / 364 = 147/364 = 21/ 52 ≈ 0.4038 ≈ 40.38%
