+830 Triangle XYZ is equilateral, with O as its center. A point P is chosen at random. Find the probability that P is closer to point O than to any of the side lengths.
+1894 Let's draw a diagram.
The Green part is where the points would satisfy the conditions.
There are 18 triangles congruent to each other in this graph. If we count, 12 of them are in the green area.
Thus, we have \(\frac{12}{18} = \frac{2}{3}\)
Thanks! :)
~Oh, and thank you Melody for the graph
+1894 Let's draw a diagram.
The Green part is where the points would satisfy the conditions.
There are 18 triangles congruent to each other in this graph. If we count, 12 of them are in the green area.
Thus, we have \(\frac{12}{18} = \frac{2}{3}\)
Thanks! :)
~Oh, and thank you Melody for the graph
+1894 I mean, it is credits to Melody. Her answer helped me understand it!
