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I'm still learning probability distribution and I'm just really confused about this. I've been stuck on this for awhile. I don't completely understand how I'm supposed to do this. Please help and show how to solve it so I can understand. Thank you.

 Feb 25, 2020
 #1
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Note   P(2)  =   1  - .41  - .38  - .08  - .02  =  .11

 

a. P( x =2)    = .11

 

b. P ( x < 2)   =  P(x  =1)   or P(x = 0)  =  .38  +  .41  = .79

 

c. P (x ≤ 2)  =    P(x = 2)  + P(x  =1)  +  P (x  = 0)   =   .11 + .38  + .41 =  .90

 

d.  P(x ≤ 1 )  =   P(x  = 1)   or P(x  = 0 ) =   .38  + .41  =   .79

 

e. P ( x  > 2)    =  P(x  = 3)  or  P ( x  =4)   =  .08 + .02   =  0.1

 

f.  P ( x = 3 or  x  =4)  =  .08  + .02  =  0.1

 

  CORRECTED   .  thanks to alan for  pointing out  my  earlier error  !!!!

 

 

cool cool cool

 Feb 25, 2020
edited by CPhill  Feb 25, 2020
 #2
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you rom

 Feb 25, 2020

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