I'm still learning probability distribution and I'm just really confused about this. I've been stuck on this for awhile. I don't completely understand how I'm supposed to do this. Please help and show how to solve it so I can understand. Thank you.
+128408 Note P(2) = 1 - .41 - .38 - .08 - .02 = .11
a. P( x =2) = .11
b. P ( x < 2) = P(x =1) or P(x = 0) = .38 + .41 = .79
c. P (x ≤ 2) = P(x = 2) + P(x =1) + P (x = 0) = .11 + .38 + .41 = .90
d. P(x ≤ 1 ) = P(x = 1) or P(x = 0 ) = .38 + .41 = .79
e. P ( x > 2) = P(x = 3) or P ( x =4) = .08 + .02 = 0.1
f. P ( x = 3 or x =4) = .08 + .02 = 0.1
CORRECTED . thanks to alan for pointing out my earlier error !!!!
