Brent rolls a fair dodecahedral die with numbers 1,2,3,...,11,12 on its faces. What is the expected number of digits in the number he obtains? Express your answer in a decimal.
The probability that he gets 1 digit is 9/12=3/4, and the probability that he gets 2 digits is 3/12 = 1/4, so the expected number of digit he obtains is:
+486 
