a bag contain 10 balls of which 6 are red and the rest are white and blue and of equal numbers. if a ball is picked at random. find the probability that is:
(a) either white or red
(b) not red
(c) blue or red
(d) white
6 are red
2 are white
2 are blue
a) P (white or red) = 2/10 + 6/10 = 8/10 = 4/5
b) P (not red) = 1 - P(red) = 1 - 6/10 = 4/10 = 2/5
c) P (blue or red) = (2/10 + (6/10) = 8/10 = 4/5
d) P (white) = 2/10 = 1/5
