A fair, standard six-sided die is tossed 8 times. The sequence of eight results is recorded to form an eight-digit number. What is the probability that the number formed is a multiple of 8?
For 8 tosses of a die, you have a total of :209,952 combinations that are multiples of 8.
Therefore, the probability is: 209,952 / 6^8 =1 / 8
