+22 he Boomtown Bears are playing against the Tipton Toros in a baseball tournament. The winner of the tournament is the first team that wins three games. The Bears have a probability of \(\frac{2}{3}\) of winning each game. Find the probability that the Bears win the tournament.
We must consider strings like BBB and BBTB. Going through the cases, we get a probability of (2/3)^3 + 3*(2/3)^3*(1/3)^2 + 6*(2/3)^3*(1/3)^4 = 304/729.
+23246 The Guest just mis-typed the final result: (2/3)3 + 3·(2/3)3·(1/3) + 6·(2/3)3·(1/3)2 = 64/81
Winning in three games: BBB
Winning in four games: BBTB, BTBB, TBBB
Winning in five games: BBTTB, BTTBB, BTBTB, TBBTB, TBTBB, TTBBB
+22 This problem has stomped me for sooooo long. Now thanks to your help, I learned how to do problems like this!
