If 8 numbers are chosen at random from the first 16 positive integers, what is the probability that an additional number chosen at random from the remaining 8 numbers is less than any of the 8 previously chosen numbers?
If 8 numbers are chosen at random from the first 16 positive integers, what is the probability that an additional number chosen at random from the remaining 8 numbers is less than any of the 8 previously chosen numbers?
Not sure but this is my attempt
I'm thinking that maybe it doesn't matter that there are 16 numbers to start with.The fact is you have 9 numbers
The chance that the smallest is at the end is 1/9
This seems too simple to be correct but I cant see what is wrong with the logic.
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If you find out the answer then please share it. Preferably with working.