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If 8 numbers are chosen at random from the first 16 positive integers, what is the probability that an additional number chosen at random from the remaining 8 numbers is less than any of the 8 previously chosen numbers? 

 Jan 14, 2022
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If 8 numbers are chosen at random from the first 16 positive integers, what is the probability that an additional number chosen at random from the remaining 8 numbers is less than any of the 8 previously chosen numbers?

 

Not sure but this is my attempt

 

I'm thinking that maybe it doesn't matter that there are 16 numbers to start with.The fact is you have 9 numbers

 

The chance that the smallest is at the end is   1/9

 

This seems too simple to be correct but I cant see what is wrong with the logic.

 

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If you find out the answer then please share it.   Preferably with working.

 Jan 14, 2022

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