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In a video game, each rocket has an \(60\%\) chance of hitting a target. Three rockets are now fired at a target. What is the probability that exactly two of the rockets will hit the target? Express your answer as a decimal to the nearest thousandth.

 Apr 14, 2022

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 #1
avatar+580 
+3

hit x hit x miss  =  .60 x .60 x .40  =  .144

hit x miss x hit  =  .60 x .40 x .60  =  .144

miss x hit x hit  =  .40 x .60 x .60  =  .144

Adding these together:                     .432

 

Used the exact method as geno3141 in the question linked below: 

https://web2.0calc.com/questions/help_69037

 Apr 14, 2022
edited by Vinculum  Apr 14, 2022
 #2
avatar+118690 
+1

3C2 * 0.6^2 * 0,4 = 3*0.36*0.4 = 0.432

 Apr 14, 2022

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