Ben rolls four fair 10-sided dice. What is the probability that exactly three of the dice show a prime number?
Assuming numbers 1-10 are on each die.......
Each of the die have (4/10) probability of rolling a prime 2, 3, 5, or 7
So.....the probability =
C(4,3) ( 4/10)^3 (6/10) = 96 / 625 ≈ .1536 ≈ 15.36%
