I need the answer to this
Right triangle XYZ has legs of length XY = 12 and YZ = 6. Point D is chosen at random within the triangle XYZ. What is the probability that the area of triangle XYD is at most 20?
The area of a right triangle is given by the formula A=21bh, where b is the base and h is the height. In this case, we know that b=12 and h=6. Therefore, the maximum possible area of triangle XYD is Amax=1/2*(12)*(6)=36.
The probability that the area of triangle XYD is at most 20 is the probability that the area of triangle XYD is less than or equal to 20. This can be calculated by dividing the area of the triangle by the maximum possible area and then multiplying by 100%. In this case, the probability is 20/36×100%=55.55%.
