In a Bombing action, there is a 50% chance that any bomb will strike the target. Two direct hits are needed to destroy the target completely. How many bombs are required to be dropped to give 99% chance or better of destroying the target?
I do not KNOW this is correct:
the chance the bomb does not hit the target is 1/2
the chance that 2 bombs do not hit the target is 1/22
the chance they DO hit the target is 1 - 1/22
for 99 % chance 1- 1/2x = .99
.01 = 1/2x take log of both sides
-2 = -.30103 x
x = 6.64 or ~~ 7 bombs