Meyer rolls two fair, ordinary dice with the numbers 1,2,3,4,5,6 on their sides. What is the probability that neither of the dice shows a square number?
+2668 There are \(36\) possible outcomes (\(6\) for the first roll and \(6\) for the second roll).
The only square numbers in the list are \(1\) and \(4\).
If we don't want either of these, there is \(4\) sucsessful options for the first role and \(4\) sucsessful options for the second roll. This means that there is \(16\) succsessful outcomes, out of the \(36\) total outcomes, meaning that the answer is \(16\over 36\), which can be simplified to \(\color{brown}\boxed{4\over9}\)
