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If 2 cards from a standard deck are selected randomly, what is the probability that at least one king or at least 1 ace occurs? (There are 4 Aces, 4 kings and 52 total cards in a standard deck.)

 Jul 4, 2022
 #1
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Probability  of   two kings  =  C(4,2) / C(52, 2)

 

Probability  of at least one ace =   1  - P (no aces)  =   1 - C(48, 2)  / C(52, 2)

 

So......total probability  is

 

[ C(4,2)/C(52, 2) ]   +  [ 1  - C(48,2)   / C(52,2)]  =    2 / 13

 Jul 4, 2022
 #2
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CPhill's answer here:https://web2.0calc.com/questions/help_9744

Guest Jul 4, 2022

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