If 2 cards from a standard deck are selected randomly, what is the probability that at least one king or at least 1 ace occurs? (There are 4 Aces, 4 kings and 52 total cards in a standard deck.)
Probability of two kings = C(4,2) / C(52, 2)
Probability of at least one ace = 1 - P (no aces) = 1 - C(48, 2) / C(52, 2)
So......total probability is
[ C(4,2)/C(52, 2) ] + [ 1 - C(48,2) / C(52,2)] = 2 / 13
CPhill's answer here:https://web2.0calc.com/questions/help_9744
