A palindrome is a number that reads the same forward as backward. If a three-digit palindrome is randomly chosen, what is the probability that it is a multiple of 2?
There are:
9 x [10^(int(3 - 1)) / 2 ]
9 x [10^(int(2/2)) ]
9 x [10^1] ==9 x 10 ==90 3-digit palindromes.
All palindromes that begin with an EVEN number, will end with an even number, such as: 202, 414, 626, 838. There are 10 palindromes for each even number for a total of: 10 x 4 ==40 - which are divisible by, or are multiples of 2.
Therefore, the probability is: 40 / 90==4 / 9
