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# ​probability

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1200 employees were surveyed about their meals preference in the cafeteria. The following

information was obtained: (write all the answers correct to 4 decimal places) (i)         What is the probability that a randomly chosen employee prefers vegetarian meal and took lunch?

(ii)        What is the probability that a randomly chosen employee took dinner or prefers non vegetarian meal?

(iii)     What is the probability that a randomly chosen employee took breakfast given that he or she prefers vegetarian meal?

Sep 29, 2017

### Best Answer

#1
+1

(i) What is the probability that a randomly chosen employee prefers vegetarian meal and took lunch?

Let's get our ratio set up:

237/1200

Plug that into the calculator

237/1200 = 0.1975

So, part (i) has an answer of 0.1975

(ii) What is the probability that a randomly chosen employee took dinner or prefers non-vegetarian meal?

In this, someone that chooses dinner AND chooses non-vegetarian meals are included.

First, let's add 206+200+191+182

206+200+191+182 = 779

So, our ratio will be 779/1200

Let's plug that into our calculator

779/1200 = 0.6491666666666667

Shorten that to 4 decimals and you get 0.6492

So, the answer for (ii) is 0.6492

(iii)     What is the probability that a randomly chosen employee took breakfast given that he or she prefers vegetarian meal?

In this, anyone who chooses a non-vegetarian meal is NOT included.

First, add 184+237+182

184+237+182 = 603

This will be the denominator of the ratio

The amount of people who chose breakfast is 184 people.

So, the ratio is 184/603

Plug this into the calculator.

184/603 = 0.3051409618573798

Shorten it to 4 decimal points and it becomes 0.3051

So, the answer to (iii) is 0.3051

I hope this helped!

Sep 29, 2017

### 1+0 Answers

#1
+1
Best Answer

(i) What is the probability that a randomly chosen employee prefers vegetarian meal and took lunch?

Let's get our ratio set up:

237/1200

Plug that into the calculator

237/1200 = 0.1975

So, part (i) has an answer of 0.1975

(ii) What is the probability that a randomly chosen employee took dinner or prefers non-vegetarian meal?

In this, someone that chooses dinner AND chooses non-vegetarian meals are included.

First, let's add 206+200+191+182

206+200+191+182 = 779

So, our ratio will be 779/1200

Let's plug that into our calculator

779/1200 = 0.6491666666666667

Shorten that to 4 decimals and you get 0.6492

So, the answer for (ii) is 0.6492

(iii)     What is the probability that a randomly chosen employee took breakfast given that he or she prefers vegetarian meal?

In this, anyone who chooses a non-vegetarian meal is NOT included.

First, add 184+237+182

184+237+182 = 603

This will be the denominator of the ratio

The amount of people who chose breakfast is 184 people.

So, the ratio is 184/603

Plug this into the calculator.

184/603 = 0.3051409618573798

Shorten it to 4 decimal points and it becomes 0.3051

So, the answer to (iii) is 0.3051

I hope this helped!

rarinstraw1195 Sep 29, 2017