​probability

(i) What is the probability that a randomly chosen employee prefers vegetarian meal and took lunch? 

Let's get our ratio set up:

 

237/1200

 

Plug that into the calculator

 

237/1200 = 0.1975

 

So, part (i) has an answer of 0.1975

 

(ii) What is the probability that a randomly chosen employee took dinner or prefers non-vegetarian meal?  

In this, someone that chooses dinner AND chooses non-vegetarian meals are included.

 

First, let's add 206+200+191+182

 

206+200+191+182 = 779

 

So, our ratio will be 779/1200

 

Let's plug that into our calculator

 

779/1200 = 0.6491666666666667

 

Shorten that to 4 decimals and you get 0.6492

 

So, the answer for (ii) is 0.6492

 

(iii)     What is the probability that a randomly chosen employee took breakfast given that he or she prefers vegetarian meal?

In this, anyone who chooses a non-vegetarian meal is NOT included.

 

First, add 184+237+182

 

184+237+182 = 603

 

This will be the denominator of the ratio

 

The amount of people who chose breakfast is 184 people.

 

So, the ratio is 184/603

 

Plug this into the calculator.

 

184/603 = 0.3051409618573798

 

Shorten it to 4 decimal points and it becomes 0.3051

 

So, the answer to (iii) is 0.3051

 

I hope this helped!