If two distinct members of the set\{ 2, 4, 12, 14, 21, 28, 98 \} are randomly selected and multiplied, what is the probability that the product is a multiple of 16? Express your answer as a common fraction.
The number of possible products = 21
Those that are multiples of 16 are
4 *12 = (4 * 4 * 3) = 16 *3
4 * 28 = (4 * 4 ( 7) = 16 * 7
12* 28 = (4 * 3) ( 4 * 7) = 16 * 21
P (multiple of 16) = 3 / 21 = 1 / 7
