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The faces of two regular dodecahedra are labeled with the numbers 1 to 12 in order to make dice. If these dice are rolled, what is the probability that the sum of the two top numbers is greater than 16?

 Nov 30, 2020
 #1
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+1

If I understand your question. 2 12-sided dice are rolled, what is the probability of getting a sum > 16?

 

The probability is [8 + 7 + 6 + 5 + 4 + 3 + 2 + 1] / 12^2 =36 / 12^2 = 1 / 4

 Nov 30, 2020
 #2
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+1

Draw a grid 12 by 12 (plus an extra row and an extra column for the 2 numbers rolled).

 

+ 1 2 3 4 5 6 7 8 9 10 11 12
1                        
2                        
3                        
4                        
5                        
6                        
7                        
8                        
9                        
10                        
11                        
12                        

 

Fill in the squares and see how many add to more than 16   etc

 Nov 30, 2020

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