The faces of two regular dodecahedra are labeled with the numbers 1 to 12 in order to make dice. If these dice are rolled, what is the probability that the sum of the two top numbers is greater than 16?
If I understand your question. 2 12-sided dice are rolled, what is the probability of getting a sum > 16?
The probability is [8 + 7 + 6 + 5 + 4 + 3 + 2 + 1] / 12^2 =36 / 12^2 = 1 / 4
Draw a grid 12 by 12 (plus an extra row and an extra column for the 2 numbers rolled).
Fill in the squares and see how many add to more than 16 etc
