Sally spins a fair spinner numbered 1-5 and rolls a fair dice.
What is the probability of obtaining a multiple of 3 and a factor of 10?
I'm assuming that we're taking about obtaining a multiple of three on the spinner and a factor of ten on the dice
The only multiple of three possible on the spinner is 3
The factors of 10 possible on the die are 1, 2 and 5
P( multiple of three on the spinner) = 1/5 = A
P(obtaining a factor of ten on the dice) = 3/6 = 1/2 = B
P( A and B) = (1/5) (1/2) = 1/10