You roll 10 12-sided dice. What is the probability of getting a sum of 68?
S=68; N=10; D=12;sumfor(k, 0, ((S - N)/D), ((-1)^k * (N nCr k) * (S - D*k - 1) nCr (N - 1))
2150363215 / 12^10==0.03472956645
