probability

NIce table.....that is what Melody was mentioning...BUT if you count the squares in your table , you will see:

There are 6 x 6 = 36 possibilities for the two dice (not 48) , so the possibility of a 12 ( 6 & 6 ) is 1/36

1/36 = 2.77 %

there are TWO 11s possible out of 36    2/36 = 5.55 % chance of rolling an 11

etc...

You know how you do a 12 by 12 grid for times tables?

well

do a 6 by 6 grid for your dice.  Maybe a red die 1 to 6 across the top and a blue die 1 to 6 down the side.

There are 36 possible outcomes when you throw your dice.

 

Just go through the grid and find all the outcomes that are favourable to what you want and the probabliliy of thowing that will be  that number over 36.

 

0	1	2	3	4	5	6
1	2	3	4	5	6	7
2	3	4	5	6	7	8
3	4	5	6	7	8	9
4	5	6	7	8	9	10
5	6	7	8	9	10	11
6	7	8	9	10	11	12

 

Counting the number of blocks on the table excluding the zero, there is 48 for both dices which means there's a 2.173913043. percent of rolling a twelve, and 4.347826087 percent of rolling a 11, and so on. All you have to do is to multiply 2.173913043 by the number of your number given on the table. That's my answer for it.