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Kendra has 5 red marbles, 4 blue marbles, and 3 white marbles. What is the probability that she draws a red marble and then a blue marble without replacing the first marble? *

 Mar 24, 2021
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the probability she draws a red marble is $\frac{5}{12}.$ 

 

since there's no replacement, we now have a pool of 11 marbles to pick from. the chance of picking a blue marble from this is $\frac{4}{11}.$


multiplying the two fractions, we have $\frac{5 \cdot 4}{12 \cdot 11} = \frac{20}{132} = \boxed{\frac{5}{33}}$

 

please confirm if this is wrong or not as my alcumus rating for counting and probability is very low sad 

 

if i get this problem right, it will be very lucky for both you and me cool

 Mar 24, 2021
edited by CentsLord  Mar 24, 2021
edited by CentsLord  Mar 24, 2021
edited by CentsLord  Mar 24, 2021

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