If I choose four cards from a standard -card deck, with replacement, what is the probability that I will end up with one card from each suit, or four Aces?
+876 1 card from each suit: (1/4)^4
4 aces: (1/13)^4
(1/4)^4 + (1/13)^4
+37146 BUT four aces would be one card from each suit.....so I think you have to correct for that ...??
