If I choose four cards from a standard -card deck, with replacement, what is the probability that I will end up with one card from each suit, or four Aces?

Guest May 9, 2021

#1**0 **

1 card from each suit: (1/4)^4

4 aces: (1/13)^4

(1/4)^4 + (1/13)^4

MathProblemSolver101 May 9, 2021

#2**0 **

BUT four aces would be one card from each suit.....so I think you have to correct for that ...??

ElectricPavlov
May 9, 2021