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If I choose four cards from a standard -card deck, with replacement, what is the probability that I will end up with one card from each suit, or four Aces?

 May 9, 2021
 #1
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1 card from each suit: (1/4)^4

4 aces: (1/13)^4

(1/4)^4 + (1/13)^4

 #2
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   BUT four aces would be one card from each suit.....so I think you have to correct for that ...??

ElectricPavlov  May 9, 2021

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