+9 A teacher was using a random group generator to split 24 different students, including A, B, and C, in 8 groups of 3. What is the probability that the 3 students, A, B, and C, are in the same group?
+4 we can use basic definition of probability to solve this
probability = successful outcomes / total outcomes
calculating total outcomes:
A has 3 options for group
B has 3 options for group
C has 3 options for group
so total possibilities = 3 * 3 * 3 = 27
now there are 3 total successful outcomes: One where all 3 go in first group one where all 3 go in 2nd group and one where all 3 go in 3rd group
so probability = 3/27 = \(\boxed{\frac{1}{9}} \)
