+0  
 
0
42
2
avatar

Hey, thanks in advance.

 

5 people are to be chosen from 4 male and 6 females, how many possible committees can be selected which include more females than males?

Guest Jul 27, 2018
 #1
avatar
0

I will give this a go!.

 

1 - First scenario: You want a committee of 5 people 4 of which must be female and 1 male:

6C4 x 4C1 =15 x 4 = 60 ways of choosing in this scenario.

 

2- Second scenario: You want a committee of 5 people 3 of which must be female and 2 male:

6C3 x 4C2 =20 x  6 =120 ways of choosing in this scenario.

 

So, the total of the two scenarios =60 + 120 = 180 ways of choosing a committee of 5 people.

Note: Somebody should check this.

Guest Jul 27, 2018
 #2
avatar
0

Perfect, except if there are 5 females, that is also an option.

there are six of these, meaning the answer is 186!

Guest Jul 27, 2018

12 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.