The Grammar club has 20 members: 10 boys and 10 girls. A 4-person committee is chosen at random. What is the probability that the committee has at least 1 boy?
+1223 total number of committees = \(\binom{20}{4} = 4845\)
number of committees without any boys = \(\binom{10}{4} = 210\)
probability: \(1 - \frac{210}{4845} = \frac{4635}{4845} = \boxed{\frac{309}{323}}\)
