+502 A bag contains 5 red b***s', 3 blue b***s' and 2 yellow b***s'. A ball is drawn and not replaced. A second ball is drawn. Draw a tree diagram and find the probability of drawing:
a) two red b***s',
b) one blue ball and one yellow ball
c) two yellow b***s'
d) two b***s' of the same colour
+227 So, I'll attempt an ASCII tree diagram.
R
/
R - Y
\
B
R
/
Y - Y
\
B
R
/
B - Y
\
B
I'm not 100% sure about that; someone else might need to check it.
a) For the first ball, there is a 5 in 10 probability of it being red, or 1/2. For the second ball, there is a 4 in 9 chance of it being red, since we took one out, or a 4/9 chance. Multiply these two fractions together to get a 2/9 probability of them both being red.
b-d) Follow above example.
+227 So, I'll attempt an ASCII tree diagram.
R
/
R - Y
\
B
R
/
Y - Y
\
B
R
/
B - Y
\
B
I'm not 100% sure about that; someone else might need to check it.
a) For the first ball, there is a 5 in 10 probability of it being red, or 1/2. For the second ball, there is a 4 in 9 chance of it being red, since we took one out, or a 4/9 chance. Multiply these two fractions together to get a 2/9 probability of them both being red.
b-d) Follow above example.
