The integers r and k are randomly selected, where 3 < r < 6 and 1 < k < 8. What is the probability that the division r/k is an integer value? Express your answer as a common fraction.
r=3, 4, 5, 6
k=1, 2, 3, 4, 5, 6, 7, 8
4 x 8 ==32 possible divisions.
3/1, 3/3, 4/1, 4/2, 4/4, 5/1, 5/5, 6/1, 6/2, 6/3, 6/6 - these all give integer values. I count 11 of them.
Therefore, the probability is: 11 / 32
