+0  
 
0
66
1
avatar

If I choose four cards from a standard 52-card deck, with replacement, what is the probability that I will end up with one card from each suit?

 Nov 6, 2018

Best Answer 

 #1
avatar+3589 
+1

\(p =\dfrac{52}{52}\dfrac{39}{52}\dfrac{26}{52}\dfrac{13}{52} = \dfrac{3}{32}\)

.
 Nov 7, 2018
 #1
avatar+3589 
+1
Best Answer

\(p =\dfrac{52}{52}\dfrac{39}{52}\dfrac{26}{52}\dfrac{13}{52} = \dfrac{3}{32}\)

Rom Nov 7, 2018

16 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.