+0  
 
0
37
1
avatar

If I choose four cards from a standard 52-card deck, with replacement, what is the probability that I will end up with one card from each suit?

Guest Nov 6, 2018

Best Answer 

 #1
avatar+2793 
+1

\(p =\dfrac{52}{52}\dfrac{39}{52}\dfrac{26}{52}\dfrac{13}{52} = \dfrac{3}{32}\)

Rom  Nov 7, 2018
 #1
avatar+2793 
+1
Best Answer

\(p =\dfrac{52}{52}\dfrac{39}{52}\dfrac{26}{52}\dfrac{13}{52} = \dfrac{3}{32}\)

Rom  Nov 7, 2018

18 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.