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If I choose four cards from a standard 52-card deck, with replacement, what is the probability that I will end up with one card from each suit?

 Nov 6, 2018

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\(p =\dfrac{52}{52}\dfrac{39}{52}\dfrac{26}{52}\dfrac{13}{52} = \dfrac{3}{32}\)

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 Nov 7, 2018
 #1
avatar+4402 
+1
Best Answer

\(p =\dfrac{52}{52}\dfrac{39}{52}\dfrac{26}{52}\dfrac{13}{52} = \dfrac{3}{32}\)

Rom Nov 7, 2018

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