A bag contains 6 red marbles, 5 blue marbles and 8 green marbles. If three marblesare drawn out of the bag, what is the probability, to the nearest 10th of a percent, that all three marbles drawn will be green?
+592 Total marbles in the bag: 6 + 5 + 8 = 19
The probability that all three marbles drawn will be green is = \(\frac{5}{19} \cdot \frac{4}{18} \cdot \frac{3}{17} = \frac{10}{969}\)
≈ 1.03%
