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A bag contains 6 red marbles, 5 blue marbles and 8 green marbles. If three marblesare drawn out of the bag, what is the probability, to the nearest 10th of a percent, that all three marbles drawn will be green?

 Mar 8, 2021
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Total marbles in the bag: 6 + 5 + 8 = 19

The probability that all three marbles drawn will be green is = \(\frac{5}{19} \cdot \frac{4}{18} \cdot \frac{3}{17} = \frac{10}{969}\)

≈ 1.03%

 Mar 8, 2021

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