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Abdul rolls a fair six-sided die and a fair four-sided die simultaneously. 

Let A be the event that the six-sided die is three and B be the event that Abdul rolls doubles (rolls the same number on each die).

What is P(A or B), the probability that the six-sided die is three or Abdul rolls doubles? _____

 

 

six-sided die ; fair four-sided die ‚Äč

1;1 2;1 3;1 4;1 5;1 6;1
1;2 2;2 3;2 4;2 5;2 6;2
1;3 2;3 3;3 4;3 5;3 6;3
1;4 2;4 3;4 4;4 5;4 6;4
Guest Nov 26, 2018

Best Answer 

 #1
avatar+3178 
+1

\(P[A \cup B] = P[A] + P[B] - P[A \cap B]\\ P[A] = \dfrac 1 6\\ P[B] = \dfrac{4}{24} = \dfrac 1 6 \\ P[A \cap B] =\dfrac{1}{24} \\ P[A\cup B] = \dfrac 1 6 + \dfrac 1 6 - \dfrac {1}{24} = \dfrac {7}{24}\)

Rom  Nov 27, 2018
 #1
avatar+3178 
+1
Best Answer

\(P[A \cup B] = P[A] + P[B] - P[A \cap B]\\ P[A] = \dfrac 1 6\\ P[B] = \dfrac{4}{24} = \dfrac 1 6 \\ P[A \cap B] =\dfrac{1}{24} \\ P[A\cup B] = \dfrac 1 6 + \dfrac 1 6 - \dfrac {1}{24} = \dfrac {7}{24}\)

Rom  Nov 27, 2018

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