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 An urn contains 6 red, 5 blue and 3 green marbles. If 2 marbles are picked at random,what is the probability that both are red?

 Jul 16, 2022
 #1
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Probability = 6/(14) * 5/13

= 3/7 * 5/13

=15/91

 Jul 16, 2022
 #2
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The total amount of marbles: \(6+5+3=14\)

The probability that your first pick is red: \(\frac{6}{14}\)

The likelihood that the second pick is red: \(\frac{5}{13}\), remember you already picked a red one!

 

Multiply them together to get: \(\frac{6}{14}\cdot\frac{5}{13}=\frac{30}{182}\), and just simplify that yourself to get the answer!

 

I hope this helped!

 Jul 16, 2022

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