An urn contains 6 red, 5 blue and 3 green marbles. If 2 marbles are picked at random,what is the probability that both are red?

Guest Jul 16, 2022

#2**+6 **

The total amount of marbles: \(6+5+3=14\)

The probability that your first pick is red: \(\frac{6}{14}\)

The likelihood that the second pick is red: \(\frac{5}{13}\), remember you already picked a red one!

Multiply them together to get: \(\frac{6}{14}\cdot\frac{5}{13}=\frac{30}{182}\), and just simplify that yourself to get the answer!

I hope this helped!

nerdiest Jul 16, 2022