An urn contains 6 red, 5 blue and 3 green marbles. If 2 marbles are picked at random,what is the probability that both are red?
+1161 The total amount of marbles: \(6+5+3=14\)
The probability that your first pick is red: \(\frac{6}{14}\)
The likelihood that the second pick is red: \(\frac{5}{13}\), remember you already picked a red one!
Multiply them together to get: \(\frac{6}{14}\cdot\frac{5}{13}=\frac{30}{182}\), and just simplify that yourself to get the answer!
I hope this helped!
