If three, standard, 6-faced dice are rolled, what is the probability that the sum of the face up integers is \(12\)?
We have 6^3 = 216 possible outcomes
Ways of rolling 12
4 , 4, 4 = 1
4, 5 , 3 = 3! = 6
4 , 6 , 2 = 3! = 6
5, 6 ,1 = 3! = 6
5 , 5 , 2 = 3
6 , 3 , 3 = 3
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25
P (12) = 25 / 216
