You roll a fair die four times. What is the probability of getting a 6 at least once?
+738 we can use complementary counting to solve this one!
the only way you can't get a 6 at least once is if you get no sixes in 4 throws.
so, if you get no sixes in four throws, there are 5 possibilities for each throw, and therefore \(5^4=625\) possibilities with no six out of the \(6^4=1296\) possibilities in total.
so you get the probability by taking the \(1296-625=671\) possibilities which must include at least one six, out of the \(1296\) possibilities altogether.
so the answer is \(\boxed{\dfrac{671}{1296}}\).
