When three standard dice are tossed, the numbers x, y, and z are obtained. Find the probability that xyz=18. If you have an answer please explain it, without an explanation the problem is useless to my education
how do you multiply three numbers to get 18
3 2 6 6 ways to roll this 326 362 632 623 236 263
3 3 2 3 ways to roll 332 323 233
631 6 ways
There are 6^3 = 216 possible rolls
12 out of 216 12 /216 or 1 / 18
Looks more like 9 to me. you can't count that first one because 3 x 2 x 6 does not equal 18
(136, 163, 233, 316, 323, 332, 361, 613, 631)>>Total = 9 ways
Probability is: 9 / 6^3 ==9 / 216==1 / 24
