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There are 17 boys and 15 girls in a Math 30 class. The teacher is selecting 7 students to represent the school on the student advisory council.

Determine the probability, to the nearest hundredth of a percentage, that at most 2 boys will be selected.

 May 12, 2021
 #1
avatar+120287 
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P(0 boys chosen  )  =   C( 15.7)  / C(30,7)

 

P( 1  boy chosen  =  [ C(17,1) * C(15,6) ] / C(30,7)

 

P (2 boys chosen   =   [ C (17,2) * C(15,5) ]  / C (30, 7)

 

 

So.....the probability is

 

[C(15,7)  + C(17,1)* C(15,6)  +  C(17,2) *C( 15,5)] / C(30,7)   ≈  25%

 

 

cool cool cool

 May 12, 2021
 #2
avatar+93 
+1

There are 17 boys and 15 girls in a Math 30 class. The teacher is selecting 7 students to represent the school on the student advisory council.

Determine the probability, to the nearest hundredth of a percentage, that at most 2 boys will be selected.

 

%=25%

 

fraction=1/4

 May 12, 2021

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