A helicopter is ascending vertically with a speed of 5.56 m/sm/s . At a height of 108 mm above the Earth, a package is dropped from the helicopter. How much time does it take for the package to reach the ground? [Hint: What is v0 for the package?]
v0=5.56 m/s
vf=0 (when it hits the ground) xo = original height xf = final height = 0
a= -9.81 m/s^2
xf = x0 + v0 t + 1/2 a t^2
o = 108 + 5.56 t + 1/2 (-9.81) t ^2
0= 108 + 5.56 t - 4.905 t^2 solve for t = 5.29 s