Given a point P(8,1) on Segment AB with A(-2,3), find the coordinates of B if AP/AB= 2/3
Given a point P(8,1) on Segment AB with A(-2,3), find the coordinates of B if AP/AB= 2/3
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m=yP−yAxP−xA=−210=−0.2
f(x)=m(x−xP)+yP
f(x)=−0.2(x−8)+1
f(x)=−0.2x+2.6
(xP−xA):(xB−xA)=2:32xB−2xA=3xP−3xA2xB=3xP−3xA+2xA2xB=3⋅8−3⋅(−2)+2⋅(−2)xB=12+3−2
xB=13
yB=−0.2⋅13+2.6
yB=0
The coordinates of B: B (13,0)
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