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Problem The expression for the surface area of a cube of side length sss is 6s^26s ​2 ​​ 6, s, start superscript, 2, end superscript. What is the surface area of a cube with side length \dfrac{3}{2} ​2 ​ ​3 ​​ start fraction, 3, divided by, 2, end fraction units?

 Aug 29, 2015

Best Answer 

 #1
avatar+23245 
+5

Total surface area = 6s2.

If  s = 3/2,  then  area  =  6 x (3/2)2  =  6 x (9/4)  =  54/4  =  13.5  sq units.

 Aug 29, 2015
 #1
avatar+23245 
+5
Best Answer

Total surface area = 6s2.

If  s = 3/2,  then  area  =  6 x (3/2)2  =  6 x (9/4)  =  54/4  =  13.5  sq units.

geno3141 Aug 29, 2015

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