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Problem:

Find the coefficient of  x^2 in the expansion of (2x-1)^5

rohitaop  May 28, 2018
edited by rohitaop  May 28, 2018
edited by rohitaop  May 28, 2018
 #1
avatar+7002 
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\((2x-1)^5 = \displaystyle\sum_{r=0}^{5}\binom5 r\cdot2^rx^r\cdot(-1)^{5-r}\)

Term in x^2 = \(\displaystyle \binom 5 2 2^2\cdot x^2\cdot (-1)^{5-2}=-40x^2\)

Therefore the coefficient is -40.

MaxWong  May 28, 2018

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