A circular sheet of paper of radius 6 inches is cut into 3 equal sectors, and each sector is formed into a cone with no overlap. What is the height in inches of the cone?

Guest Jun 25, 2018

The  circumference of  the base  of each cone will be the arc length of one of the sectors  =


2 pi (6)  / 3  =  4 pi  inches


So....the radius, r, of each cone (in inches) is given  by :


4pi  =  2 pi * r

4  = 2r

2  = r   


And the slant height of each cone  is the radius of the original circle


And the radius of the cone and its height will form two legs of a right triangle with a hypotenuse of 6 inches  (the slant height)


So...using the Pythagorean Theorem, the cone height, h, is given by :


h  = √[ slant height^2  - radius^2 ]  =  √ [ 6^2  - 2^2 ] = √32  =  4√2  inches



cool cool cool

CPhill  Jun 25, 2018

38 Online Users


New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.