+50 Work out the width of a rectangle with area √5 and length 1+√5.
Give your answer in the form a+b√5, where a and b are rational constants
+118653 Hi xrabia :)
Work out the width of a rectangle with area √5 and length 1+√5.
Give your answer in the form a+b√5, where a and b are rational constants
\(w*(1+\sqrt5)=\sqrt5\\ w=\frac{\sqrt5}{1+\sqrt5}\\ w=\frac{\sqrt5}{1+\sqrt5}\times \frac{1-\sqrt5}{1-\sqrt5}\\ w=\frac{\sqrt5(1-\sqrt5)}{(1+\sqrt5)(1-\sqrt5)}\\ w=\frac{\sqrt5-5}{(1-5)}\\ w=\frac{\sqrt5-5}{-4}\\ w=\frac{5-\sqrt5}{4}\\ w=1.25+(-0.25)\sqrt5\)
