Problem

Let the numbers be     n-1     n      n+1    and   n+2

   The numbers are ALMOST 

 n^4 = 461^2 - 1 = 212520      <======take 4th root of both sides

n ~~  21 

                   so try  20 21 22 23    =  212520     Bingo !   On first try .......

I think to do n(n+1)(n+2)(n+3)=461^2 -1, then do

(n^2 +n)(n+2)(n+3)=212520

(n^3+3n^2+2n)(n+3)=212520

n^4+3n^3+3n^3+9n^2+2n^2+6n=212520

n^4 + 6n^3 + 11n^2 + 6n = 212520

What now? Or is there another way to do this?

Pls help