+0  
 
+1
34
1
avatar+117 

how do you work this out

petri  Nov 28, 2018
 #1
avatar+92808 
+1

First, multiply the first two

(x - 1) ( x + 2)  =    x^2 - 1x + 2x - 2  = x^2 + x - 2

 

Now,  multiply   

 

( x^2 + x - 2) (x + 3)

Multiply the  three terms in the parenthses by each of the terms in the second set of parentheses

So we have

 

x^2 * x  +  x* x  -2*x  =   x^3 + x^2 - 2x       (1)

 

x^2 * 3 + x*3   -2*3  =  3x^2 + 3x - 6    (2)

 

Combine (1) and (2)   and we have

 

x^3 + x^2 + 3x^2 + 3x - 2x - 6  =

 

x^3 + 4x^2 +1x - 6

 

 

cool cool cool

CPhill  Nov 28, 2018
edited by CPhill  Nov 28, 2018

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