\(\int dx/(x^3-8) \)
becomes:
\(dx/(x-2)(x^2+2x+4) \rightarrow \int \frac{A}{x-2}+\frac{Bx+C}{x^2+2x+4}\)
and this is how i arranged it:
\(1=(x^2+2x+4)A+(x-2)(Bx+C)\)
and now he wants me to arrange it a simplier way or better way? he gave me a clue and that it starts with 0x^2-1= and that i should figure out the rest. please do help if you have an idea on what it is that he is trying to make me perform here.
