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The height, h, in meters above ground, of a projectile at any time, t, in seconds, after the launch is defined by the function h(t) = −4t^2 + 19t + 5. The graph is shown below. When rounded to the nearest tenth, what is the maximum height reached by the projectile, how long did it take to reach its maximum height, and when did the projectile hit the ground?

 Mar 23, 2021
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See the graph here :  https://www.desmos.com/calculator/vxitx7lzzu   (x  is used instead of t......same difference)

 

 

Max height  =  27.6 ft

 

 Time to reach max ht =  2.4 sec

 

The projectile  hit  the ground at  5 sec

 

 

cool cool cool

 Mar 23, 2021

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