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A ball is thrown horizontally from a building 63.0 m high with a speed of 25.0 m/s. Find the (a)vertical and horizontal components of the ball's initial velocity, (b) time flight, (c) distance from the foot of the building where the ball will strike the ground, and (d) velocity when the ball will strike the ground.

 
Guest Sep 13, 2018

Best Answer 

 #1
avatar+12679 
+2

The ball is thrown HORIZONTALLY, so the initial vertical velocity = 0 m/s   and the initial horizontal velocity = 25 m/s.

1 The ball's 'x' position is given by    x = x0 + v0t           x0=0    vo=25   (there is no 'a' in the x direction)

2 The ball's  'y' position is   y = yo + vot  + 1/2 a t^2      where yo=63  vo=0  a = -9.8 m/s^2

 

Use 2 to find t when y = 0  (when the ball hits the ground)

    t = 3.59 s

Use this time to find the x distance the ball travels before hitting the ground (equation 1)

    x = 25(3.59) = 89.64 m

 

3 Velocity when it hits the ground will be BOTH an x velocity and a y velocity.

     the x velocity is given as  25 m/s

     the y velocity is given by  vy = vo + at       v0= 0    a = -9.8 m/s^2        t = 3.59 s

      vy = -9.8(3.59) = -35.18 m/s

  

     'VECTORIALLY' add x and y together to get the velocity MAGNITUDE    sqrt(25^2 + 35.18^2)= 43.16 m/s

 
ElectricPavlov  Sep 13, 2018
edited by ElectricPavlov  Sep 13, 2018
 #1
avatar+12679 
+2
Best Answer

The ball is thrown HORIZONTALLY, so the initial vertical velocity = 0 m/s   and the initial horizontal velocity = 25 m/s.

1 The ball's 'x' position is given by    x = x0 + v0t           x0=0    vo=25   (there is no 'a' in the x direction)

2 The ball's  'y' position is   y = yo + vot  + 1/2 a t^2      where yo=63  vo=0  a = -9.8 m/s^2

 

Use 2 to find t when y = 0  (when the ball hits the ground)

    t = 3.59 s

Use this time to find the x distance the ball travels before hitting the ground (equation 1)

    x = 25(3.59) = 89.64 m

 

3 Velocity when it hits the ground will be BOTH an x velocity and a y velocity.

     the x velocity is given as  25 m/s

     the y velocity is given by  vy = vo + at       v0= 0    a = -9.8 m/s^2        t = 3.59 s

      vy = -9.8(3.59) = -35.18 m/s

  

     'VECTORIALLY' add x and y together to get the velocity MAGNITUDE    sqrt(25^2 + 35.18^2)= 43.16 m/s

 
ElectricPavlov  Sep 13, 2018
edited by ElectricPavlov  Sep 13, 2018

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