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15 students in 6A are divided into 3 groups for a party , 3 students are organizers , 4 students are planners and 8 students are responsible for the food 

Mandy , Helen and Sue are 6A students are responsible for the party

find the probability that thy are in the same group

thanks

 Jan 26, 2015

Best Answer 

 #2
avatar+118703 
+10

 

(3C3 + 4C3 + 8C3)/15C3

 

((3!3!×(33)!)+(4!3!×(43)!)+(8!3!×(83)!))(15!3!×(153)!)=61455=0.1340659340659341

 

There you go, Alan's answer and my answer look different but they work out the same because the 3! in mine cancels out.  

How about that!      

 Jan 27, 2015
 #1
avatar+33657 
+5

This is (nbr of ways of arranging 3 people in a group of 3 + nbr of ways of arranging 3 people in a group of 4 + nbr of ways of arranging 3 people in a group of 8)/(nbr of ways of arranging 3 people in a group of 15):

 

((3!(33)!)+(4!(43)!)+(8!(83)!))(15!(153)!)=61455=0.1340659340659341

.

 Jan 26, 2015
 #2
avatar+118703 
+10
Best Answer

 

(3C3 + 4C3 + 8C3)/15C3

 

((3!3!×(33)!)+(4!3!×(43)!)+(8!3!×(83)!))(15!3!×(153)!)=61455=0.1340659340659341

 

There you go, Alan's answer and my answer look different but they work out the same because the 3! in mine cancels out.  

How about that!      

Melody Jan 27, 2015

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