If (x + 2)(3x^2 + x + 5) = Ax^2 + Bx^2 + Cx + D, what is the value of A + B - C - D?
+592 (x + 2)(3x2 + x + 5)
= 3x3 + x2 + 5x + 6x2 + 2x + 10
= 3x3 + 7x2 + 7x + 10
A = 3
B = 7
C = 7
D = 10
A + B - C - D
= 3 + 7 - 7 - 10
= 10 - 17
= -7, which is your answer :)
